For today, we have the solution to another definite integral:

Back in Monday Math 6, I demonstrated that for any real n, . A simple change of variables from this allows us to see that as well (the change is ; then rename the variable to x).

Now, looking at our present integral, one might note that

. Thus .

The key is to now replace x in this expression with n, and a with , and we have something we can obtain from the integrand of . Specifically:

.

The internal integral is the one we already established is , for any real value of y. Hence

.

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Tags: Integration, Math, Monday Math

This entry was posted on June 9, 2008 at 12:50 am and is filed under Math/Science. You can follow any responses to this entry through the RSS 2.0 feed.
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