Physics Friday 97

Suppose we have a cube, of edge length L, with mass M symmetrically distributed so that the geometric center of the cube is the center of mass. Suppose we have a fluid with density ρ, such that (the average density of the cube is less than that of the fluid), so that the cube will float in the fluid. If the cube is floating such that the upper face is entirely outside the fluid, and is tipped toward one edge by an angle θ from the horizontal, then what is the torque on the cube about its center?

Let us define the ratio of the densities of the cube and the fluid as xi;, so that . Then 0<xi;<1. Then via Archimedes’ Principle, the weight of fluid displaced equals the weight of the cube, and thus the volume Vd of fluid displaced can be found:
or, using M=ξρL3, Vd=ξL3, and xi; is also the fraction of the cube submerged.

Figure 1

Now, if it is tilted at an angle θ, the submerged portion is a trapezoidal prism; if the trapezoid has bases b1 and b2, then it has area , and thus the prism has volume , which, equating to the above, tells us
Our geometry tells us that ; combining, we see

and to keep the upper face “dry,” we have

Now, the center of buoyancy is located at the centroid of the trapezoidal prism. By symmetry, this center will be in the plane halfway between the trapezoidal faces of the prism. Using xy coordinates on this plane with the origin at the center of the cube and with the axes along those of the cube, we find the center of buoyancy to be the centroid of the cross-section trapezoid.

Figure 2

Now, using these coordinates, we see that the trapezoid is the region , ; the area of the trapezoid is A=ξL2, so performing the double integrals for the centroid, we have


Figure 3

Now, to convert these to coordinates with horizontal and vertical axes, we rotate coordinates by θ. If x’ is our horizontal axis and y’ our vertical axis, then
, so our center of buoyancy in these coordinates (with origin still at the center of our cube) is

And so the torque is, with positive torque being in the direction to decrease θ


Tags: , , , , ,

Leave a Reply

Fill in your details below or click an icon to log in: Logo

You are commenting using your account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

%d bloggers like this: